PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
c=-5/2
c=7/2
c=4
c=7
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OpenStudy (magbak):
\[25^(2c)=\sqrt5^(4c-10)\]
OpenStudy (magbak):
@primeralph @Jamierox4ev3r @Callisto @Hero
OpenStudy (magbak):
Which of the following is the solution to the equation
OpenStudy (primeralph):
Can you try to input the question better?
OpenStudy (magbak):
Ok
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OpenStudy (magbak):
\[25^(2c)=\sqrt5^(4c-10)\]
OpenStudy (magbak):
25^(2c)=sqrt(5)^(4c-10)
OpenStudy (primeralph):
Same thing.
OpenStudy (magbak):
This is how it is given to me
OpenStudy (magbak):
That is not a option.
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OpenStudy (magbak):
Even if you simplify that you get -5
OpenStudy (magbak):
@primeralph
OpenStudy (primeralph):
Solve for c.
OpenStudy (magbak):
It is -5
OpenStudy (magbak):
See that is not an answer
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OpenStudy (primeralph):
Tag someone else to see.
OpenStudy (magbak):
Ok
OpenStudy (magbak):
@Hero @Callisto @ash2326
OpenStudy (magbak):
@Luigi0210 @tkhunny
OpenStudy (magbak):
@bahrom7893
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OpenStudy (magbak):
@nincompoop
OpenStudy (bahrom7893):
\[25^{2c}=\sqrt{5}^{4c-10}\]?
OpenStudy (magbak):
yes
OpenStudy (luigi0210):
Change the bases then, do you know how?
OpenStudy (bahrom7893):
okay, i'll give you one hint:
\[25=5^2\]
\[\sqrt{5}=5^{1/2}\]
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OpenStudy (magbak):
What is that supposed to mean.
OpenStudy (luigi0210):
It means change them so they have the same base
OpenStudy (bahrom7893):
\[25^{2c}=\sqrt{5}^{4c-10}\]it means rewrite this so that there are only 5s on the bottom.
OpenStudy (magbak):
Oh
OpenStudy (magbak):
It is A.
Correct me if I am wrong
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OpenStudy (bahrom7893):
no guessing, show us the solution
OpenStudy (magbak):
Well I squared both sides so that is what I got.
@campbell_st
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OpenStudy (luigi0210):
Should I keep going?
OpenStudy (magbak):
PLease
OpenStudy (luigi0210):
Continuing off of what bah said, change the bases
OpenStudy (magbak):
HOW
OpenStudy (luigi0210):
Okay.. you know that:
\[25=5^2\]
and \[\sqrt{5}=5^{1/2}\]
right?
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OpenStudy (magbak):
Yes
OpenStudy (magbak):
Now what
OpenStudy (luigi0210):
Change the bases in your equation:
\[25^{2c}=\sqrt{25}^{4c-10}\]
is the same as:
\[5^{2(2c)}=5^{1/2(4c-10)}\]
When you have same bases you can just set the exponents equal to each other:
2(2c)=1/2(4c-10)
OpenStudy (magbak):
I AM LOST
OpenStudy (magbak):
@agent0smith
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OpenStudy (primeralph):
8c = 4c-10.
OpenStudy (luigi0210):
I really don't know how to make it any more simpler..
OpenStudy (magbak):
OK @primeralph
OpenStudy (magbak):
It is A like I SAID THE FIRST TIME
OpenStudy (primeralph):
Yeah.
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OpenStudy (magbak):
THNX @primeralph
OpenStudy (magbak):
MEPS WHAT YOU LOOKING AT KEEP MOVING
OpenStudy (anonymous):
Make me
OpenStudy (primeralph):
Meps.
OpenStudy (anonymous):
yo prime... its the latex
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OpenStudy (magbak):
Just joking relax
OpenStudy (magbak):
I like your picture
OpenStudy (anonymous):
come at me bro
OpenStudy (campbell_st):
ok... all you need to do is have both sides mof the equation with the same base... which will be 5
and apply the power of a power law
\[(x^a)^b = x^{a \times b}\]
so you'll have
\[(5^2)^{2c} = (5^{\frac{1}{2}})^{4c - 10}\]
apply the power of a power law
\[5^{2 \times 2c} = 5 ^{\frac{1}{2} \times (4c -10)}\]
so you are looking at
\[5^{4c}= 5^{2c - 5}\]
since the based are the same you can equate the powers
so you need to solve
4c = 2c - 5
for c
hope this makes sense