can someone please show me the full reaction (i.e step wise) when Cu 2+ aqueous is slowly being added with NH3 until excess. please show me how the light blue ppt is formed and subsequently the dark blue solution.
When copper is reacted with ammonia, you get a complex coordinate complex, \([Cu(NH_3)_4]^{2+}\) which is the light blue that you're referring to. According to your stoichiometric equation, \(Cu^{2+}~_{(aq)} + 4 NH_3~_{(aq)} \rightarrow [Cu(NH_3)_4]^{2+}~_{(aq)}\)
sorry but i need to know the step wise reaction
so i formed Cu(H2O)4(OH)2 which is my light blue ppt. what is the reaction next if my light blue ppt react with excess ammonia?
i know Cu(NH3)4(H2O) 2+ forms but how? and whats the full eqn?
its a distorted octahedral structure, the water has a coordinate bond which is longer than the NH3 dative covalent bond
I think the water is an intermediate, but water isn't a very strong bonding molecule, which is where you get the release to get the tertiaryamine complex.
yea but im used to writing out the h2o.. so how do i get my dark blue solution from my light blue ppt?
I don't think you can form an octahedral species with copper.
I gotta step out for a bit, if someone else hasnt helped you then i will when i get back.
Just do it one at a time [Cu(H2O)4]^2+ + NH3 <-> [Cu(NH3)(H2O)3]^2+ [Cu(NH3)(H2O)3]^2+ + NH3 <-> [Cu(NH3)2(H2O)2]^2+
i'm not sure at what point the ppt is formed
Yes, at some point, the reaction is reversible.
hmmm ok thx!
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