Question

The sum of three consecutive integers is 42. Find the Integers.

Answer 1

x+(x+1)+(x+2)=42??????

Answer 2

does that look right to anyone?

Answer 3

Yes that is absolutely right!!!

Answer 4

it's nicer IMHO to label the middle \(n\) and so that our three are \(n-1,n,n+1\) -- when you sum them they cancel out nicely

Answer 5

Isaiah will you please help me with this?

Answer 6

ok so its x+(x+1)+(x+2)=42

Answer 7

Yes, I've solved and verified. You are right!!! Simply solve for x

Answer 8

I'm trying to remember how to do this

Answer 9

hmmm

Answer 10

When you sum them up it becomes 3x+3=42. Solve for x...

Answer 11

3x+3=42??

Answer 12

ok wow that took forever

Answer 13

lol

Answer 14

x=13 got it thanks

Answer 15

If I didn't need to pass this class I would of left that problem a long time ago

Answer 16

its not adding up to 42

Answer 17

Try again :)

Answer 18

alternatively, we have \(n-1,n,n+1\) our three consecutive integers and their sum is:$$(n-1)+n+(n+1)=42\\3n=42\\n=\frac{42}3=\frac{2\times21}3=2\times7=14$$hence our integers are \(13,14,15\). they do indeed sum to \(42\)

Answer 19

they dont add up to 42?

Answer 20

yeah they do
https://www.google.com/search?q=13%2B14%2B15

Answer 21

@Algebra2013 13+(13+1)+(13+2) = what??????

Answer 22

wait a minute here

Answer 23

I put in 13+(14+1)+(15+2)=42

Answer 24

I'm an idiot. thanks guys

Answer 25

hehe we all make silly little mistakes :-p