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Can you use the Law of Cosines in the triangle below? Why or why not? http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawofCosinesShortAnswerQuiz/Geometry_8.4.14_Quiz_FINAL_4q.gif
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what are you trying to find?
if you can use the law of cosines
i said yes cuz all sides are given
there must be one included angle. that's why you cannot use Law of sin or cosin on the given problem
because no angle is given.
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the law of sines requires an angle. it seems to me that an angle is not required for a COsines
here is Law cosines \[\Large c^2=a^2+b^2-2abcos(\lambda) \] where is \[\lambda \] is the angle opposite to side of length c
ahhh i see
one angle is required in Law of cosines as well .
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