Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

What is the solution of the matrix equation?

OpenStudy (anonymous):

|dw:1375549865618:dw|

OpenStudy (amistre64):

Ax=b, if it has a solution, can be determined by the augment: (A|b) to (I|x)

OpenStudy (anonymous):

do you know how to invert a matrix?$$A=\begin{bmatrix}9&4\\2&1\end{bmatrix}\\A^{-1}=\frac1{\det A}\begin{bmatrix}1&-4\\-2&9\end{bmatrix}=\frac1{9(1)-4(2)}\begin{bmatrix}1&-4\\-2&9\end{bmatrix}=\begin{bmatrix}1&-4\\-2&9\end{bmatrix}$$

OpenStudy (anonymous):

so$$Ax=\begin{bmatrix}9&-6\\-1&-8\end{bmatrix}\\A^{-1}Ax=\begin{bmatrix}1&-4\\-2&9\end{bmatrix}\begin{bmatrix}9&-6\\-1&-8\end{bmatrix}\\x=\begin{bmatrix}1&-4\\-2&9\end{bmatrix}\begin{bmatrix}9&-6\\-1&-8\end{bmatrix}$$

OpenStudy (anonymous):

multiplying we get:$$x=\begin{bmatrix}1&-4\\-2&9\end{bmatrix}\begin{bmatrix}9&-6\\-1&-8\end{bmatrix}=\begin{bmatrix}1(9)+-4(-1)&1(-6)+-4(-8)\\-2(9)+9(-1)&-2(-6)+9(-8)\end{bmatrix}=\begin{bmatrix}13&26\\-27&-60\end{bmatrix}$$

OpenStudy (anonymous):

..so what the next step?

OpenStudy (anonymous):

do i multiply that all as a whole to get 13, -27 etc?

OpenStudy (anonymous):

@oldrin.bataku

OpenStudy (anonymous):

@Buddhayourlord&savoir that matrix at the end is the product evaluated

OpenStudy (anonymous):

Are you insisting thats the answer? I have multiple choice and none of this matches :/

OpenStudy (anonymous):

OpenStudy (anonymous):

;-; @amistre64 can you please lead me through this?

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

this agrees with my solution

OpenStudy (anonymous):

:/

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!