How do you solve this inequality? |x²+2x|>2
consider that \(|x^2+2x|>2\) is the same thing as saying either \(x^2+2x>2\) or \(x^2+2x<-2\) (if you don't believe me convince yourself)
... which means we have two quadratic inequalities:$$x^2+2x-2>0\\x^2+2x+2<0$$do you know how to solve these?
same way you'd any other absolute value inequality as far as I know the only difference is that is a quadratic function, thus you'd end up with 2 pairs of values for "x"
I think the main problem I'm having is the fact that both of those don't factor normally, so would I just use the quadratic formula?
Pretty much.
Alright, thanks!
yes @OddlyWeird; also note that both are parabolas that open UPWARD, hence if they cross the x-axis they'll look like this:|dw:1375552704370:dw|
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