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Six boys and six girls sit in a row at random. Find the probability that (a) the six girls sit together (b) the boys and girls sit alternatively.
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Try simplifying the problem and work backwards, what if it was 2boys and 2 girls?
total ways to arrange 12! girls sit together : 7C1*6!*6! (7c1 to select the seats for girls and then arrange boys with 6!. The second 6! is for arranging girls)
@ankit042 How do we get 7C1?
|dw:1375554753408:dw| Girls can have seven different positions
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