PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf.

Part 1: Describe the sigma notation used in answering the question above. (2 points)

Part 2: Show all your work and answer the question. (3 points)

@CarlosGP @primeralph @Loser66

Question

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
I WILL AWARD MEDAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. 

Part 1: Describe the sigma notation used in answering the question above. (2 points) 

Part 2: Show all your work and answer the question. (3 points) 

@CarlosGP @primeralph @Loser66

loser66 · Answer

@magbak, tell me what you think

magbak · Answer

I think it is $$\sum_{n=4}^{6} 8+4(n)$$

anonymous · Answer

n has to move from n=1 to n=6

anonymous · Answer

oops! sorry loser66

loser66 · Answer

why? explain

magbak · Answer

$$\sum_{n=1}^{6}8+4(n)$$

anonymous · Answer

WIth that expression, what would be the width of the first computer? (n=1)

magbak · Answer

It tells you it is 8 inches.
The second is 12
3=16
4=20
5=24
6=28

anonymous · Answer

Yes but what is the value of the expression 8+4n when n=1?

magbak · Answer

12

anonymous · Answer

then n=1 is not your first computer, which means something is wrong in the expression 8+4n

anonymous · Answer

sure!

magbak · Answer

Oh so the equation is $$\sum_{n=0}^{6} 8+4n$$

primeralph · Answer

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