Help me with this please?
what did you get as an answer? when you tried to work it out
Thats the problem, I'm not sure how to work it out.
Oh wait... never mind. This sin't the problem. I understand this one :)
isn't*
haha ok(:
This one sort of confuses me :\
\[3+5\sqrt{49}\]
@ceejays Thank you for answering but thats not the problem I need help with. Sorry, it was a mistake posting it and besides, the answer you gave isn't one of the selection.
give me a second @HaperFink22 and i will solve that problem
what are the answers
+1.6
@ceejays
@papsmurf +1.6? Thats the answer you got? How?
hang on i see where i messed up at
what are the answers?
@HaperFink22 do you know how to cross multiply over the equals sign? Also, since the denominator (x -4) is the same on both sides, you can actually just drop both denominators... leaving you with... x = 4
the last one is what i got as well
But note you can only drop both denominators because they're exactly equal (x-4 on both). If they're different, you have to cross multiply.
So the subtraction sign doesn't make the number a negative?
When you cross multiply?
If you were to cross multiply, which makes this question a lot more work than is needed by dropping both denominators, you'd get: \[\Large x(x-4) = 4(x-4)\]
I believe this question has no solutions.
@vinnv226 if you read other responses you'd know that's obviously not the case. Which you then have to expand \[\Large x^2 - 4x = 4x- 16\]And get it all equal to zero, but subtracting 4x from both sides, and subtracting 16 from both sides:\[\Large x^2 - 8x +16 =0\]then factor it.
@agent0smith Solve that, then plug your solution into the original problem, and you'll see why there are no solutions.
Hmm, good point... odd that the answer key only offers real number solutions.
Nonetheless, you could've easily pointed that out in your first post... "If you plug in x=4, you get a zero denominator."
As it was mentioned earlier, the denominators are the same, so you don't even have to cross multiply. You can just set the numerators equal, so x=4. But you need to check your solutions in the original
Okay, thank you guys! :)
No prob. I think the answer key was somewhat flawed, it should have a "no solution" option.
Hi, there is no solution in the real number set for x, since x cannot be 4, which makes the denominator zero
oh sorry, just read the above comments, I've stated the obvious :D
Join our real-time social learning platform and learn together with your friends!