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Mathematics 15 Online
OpenStudy (anonymous):

Help me with this please?

OpenStudy (anonymous):

OpenStudy (anonymous):

what did you get as an answer? when you tried to work it out

OpenStudy (anonymous):

Thats the problem, I'm not sure how to work it out.

OpenStudy (anonymous):

Oh wait... never mind. This sin't the problem. I understand this one :)

OpenStudy (anonymous):

isn't*

OpenStudy (anonymous):

haha ok(:

OpenStudy (anonymous):

This one sort of confuses me :\

OpenStudy (anonymous):

\[3+5\sqrt{49}\]

OpenStudy (anonymous):

@ceejays Thank you for answering but thats not the problem I need help with. Sorry, it was a mistake posting it and besides, the answer you gave isn't one of the selection.

OpenStudy (anonymous):

give me a second @HaperFink22 and i will solve that problem

OpenStudy (anonymous):

what are the answers

OpenStudy (anonymous):

+1.6

OpenStudy (anonymous):

@ceejays

OpenStudy (anonymous):

@papsmurf +1.6? Thats the answer you got? How?

OpenStudy (anonymous):

hang on i see where i messed up at

OpenStudy (anonymous):

what are the answers?

OpenStudy (anonymous):

OpenStudy (agent0smith):

@HaperFink22 do you know how to cross multiply over the equals sign? Also, since the denominator (x -4) is the same on both sides, you can actually just drop both denominators... leaving you with... x = 4

OpenStudy (anonymous):

the last one is what i got as well

OpenStudy (agent0smith):

But note you can only drop both denominators because they're exactly equal (x-4 on both). If they're different, you have to cross multiply.

OpenStudy (anonymous):

So the subtraction sign doesn't make the number a negative?

OpenStudy (anonymous):

When you cross multiply?

OpenStudy (agent0smith):

If you were to cross multiply, which makes this question a lot more work than is needed by dropping both denominators, you'd get: \[\Large x(x-4) = 4(x-4)\]

OpenStudy (anonymous):

I believe this question has no solutions.

OpenStudy (agent0smith):

@vinnv226 if you read other responses you'd know that's obviously not the case. Which you then have to expand \[\Large x^2 - 4x = 4x- 16\]And get it all equal to zero, but subtracting 4x from both sides, and subtracting 16 from both sides:\[\Large x^2 - 8x +16 =0\]then factor it.

OpenStudy (anonymous):

@agent0smith Solve that, then plug your solution into the original problem, and you'll see why there are no solutions.

OpenStudy (agent0smith):

Hmm, good point... odd that the answer key only offers real number solutions.

OpenStudy (agent0smith):

Nonetheless, you could've easily pointed that out in your first post... "If you plug in x=4, you get a zero denominator."

OpenStudy (anonymous):

As it was mentioned earlier, the denominators are the same, so you don't even have to cross multiply. You can just set the numerators equal, so x=4. But you need to check your solutions in the original

OpenStudy (anonymous):

Okay, thank you guys! :)

OpenStudy (agent0smith):

No prob. I think the answer key was somewhat flawed, it should have a "no solution" option.

OpenStudy (anonymous):

Hi, there is no solution in the real number set for x, since x cannot be 4, which makes the denominator zero

OpenStudy (anonymous):

oh sorry, just read the above comments, I've stated the obvious :D

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