Question

The length of a rectangle is 5yd more than twice its width, and the area of the rectangle is 63yd^2. Find the dimensions of the rectangle.

Answer 1

Given:
Area of the rectangle = 63yd^2
Length = 2W+5 yd
Width = W

Answer 2

Area = Length x Width
63 yd^2 = (2w+5) x w
distribute w
63 yd^2 =2w^2 +5w
equate to zero
2w^2 +5w - 63yd^2 =0
use quadratic equation
(w - 4.5) (w + 7)
transpose value
w = 4.5
w = -7
Since w = -7 is a negative value we wont use it because it almost impossible that length is a negative value. we will then use w =4.5
Since LENGTH = 2W + 5
L = 2(4.5) + 5
L = 14

Therefore we conclude that
W = 4.5 yds and L = 14 yds

Answer 3

thank you

Answer 4

Thankkkk you!