Question

if x has a poisson distribution with u=3, what is the probability that x=3

Answer 1

\[P(x=3)=\frac{3^3e^{-3}}{3!}\]if i remember correctly

Answer 2

ok that was wrong
general form is
\[P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!}\]

Answer 3

compute via a calculator, although
\[\frac{3^3}{3!}=\frac{3^2}{2}=\frac{9}{2}\] you will still need a calculator for \(e^{-3}\) though