Question

I need help with setting up this problem James, Kim, and Katrina each bought lemonade at different stores. James paid $6 per gallon, Kim paid $8 per gallon, and Katrina paid $11 per gallon. Between the three of them, 25 gallons were purchased. If Kim bought 4 more gallons than Katrina and they pooled their lemonade together to sell for $8 per gallon, find the number of gallons James, Kim and Katrina each purchased.

Answer 1

K = Kim
J = James
X = Katrina

K + J + X = 25
K = X + 4

K + J + X = 25
X + 4 + J + X = 25
2X = 21 - J
X = (21 - J)/2

this is not the answer....I am stuck....Let me tag someone

Answer 2

@mathstudent55 ....help

Answer 3

@whpalmer4 ...help

Answer 4

@genius12 ...help

Answer 5

K8 + J6 + X11 = 8 ??? That doesn't make sense

Answer 6

@satellite73 ...help

Answer 7

oh....8 * 25

Answer 8

k = katrina
j = james
m = kim

k + j + m = 25
11k + 6j + 11m = 8*25
m = k + 4

Answer 9

I had you 2nd equation but I didn't multiply the 8 * 25

Answer 10

typo...your

Answer 11

Why does the 8*25 matter?

Answer 12

"they pooled their lemonade together to sell for $8 per gallon"

Answer 13

and they bought 25 gal

Answer 14

So the 8*25=200 and would you plug numbers into the second equation to get the answer?

Answer 15

You solve the system of two equations in two variables, j and k after making the proper substitutions.

Answer 16

11k+6j+11m=200
-11 -11
6j+11m=189
-11 -11
6j/6=178/6
j=29.6 repeating can't be right

Answer 17

you cant subtract 11 if its 11k

Answer 18

then what would you do

Answer 19

we know that m = k + 4

Answer 20

Sorry, it's 8m not 11m

Answer 21

Would you solve that equation first

Answer 22

k = katrina
j = james
m = kim

k + j + m = 25
11k + 6j + 8m = 8*25
m = k + 4

Answer 23

Since I messed up, I might as well just post the steps. I meant 8m the first time...it was a typo.

Answer 24

thanks Hero...your a....well...a hero....your name speaks for itself :)

Answer 25

Thank you

Answer 26

Kristen.....medal for Hero

Answer 27

Actually, there's another typo. I should have gotten 200 for that second equation.

Answer 28

I plugged the numbers back in but I didn't get 200 for the second equation

Answer 29

And I know why...

Answer 30

my eye blinked....I didn't even notice

Answer 31

k + j + (k + 4) = 25
11k + 6j + 8(k + 4) = 200

2k + j = 21
19k + 6j = 168

12k + 6j = 126
19k + 6j = 168

7k = 42
k = 6
m = k + 4 = 6 + 4 = 10
j = 9

Answer 32

There we go, that should work.

Answer 33

good catch :)

Answer 34

that's what I like about algebra. You can always plug back in to find your mistakes.

Answer 35

Where did you get 12 and 126?

Answer 36

I multiplied both sides of 2k + j = 21 by 6

Answer 37

I know I may have confused you with what I said beforehand.

Answer 38

I understand now thank you:)