Question

A and B are two independent events. The probability that both A and B occur is 1/6 and the probability that neither of them occurs is 1/3. Find the probability of the occurrence of A.

Answer 1

@genius12

Answer 2

P(A int B) = P(A) * P(B)

Answer 3

How ?

Answer 4

since the events are independent..

Answer 5

oh wao. @satellite73 you gave me the clear conception.


and hey that's calles a True Experienced Guru :) Thankyou Sir.

Answer 6

*called

Answer 7

your way of explaning me using venn-diagram gave me help

Answer 8

well we are not done just by the picture
you have to use independence as well

Answer 9

ya I know

Answer 10

\[P(A)+P(B)-P(A\cap B)=P(A\cup B)=\frac{2}{3}\]

Answer 11

so \(P(A)+P(B)=\frac{5}{6}\)

Answer 12

ok

Answer 13

i think there is no other way but to solve \[P(A)P(B)=\frac{1}{6}, P(A)+P(B)=\frac{5}{6}\]