Please help, I want guidance not answers please work through it with me, medal to best guide :)
Jose is paying for an eleven dollar meal using bills in his wallet. He has four one dollar bills, two five dollar bills, and two ten dollar bills. If he selects two bills at random, one at a time from his wallet, what is the probability that he will choose a ten dollar bill and a one dollar bill to pay for the meal? Show your work.
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jimthompson5910 (jim_thompson5910):
focus on the first part: what is the probability he will choose a 10 dollar bill (ignore the second selection for now)
jimthompson5910 (jim_thompson5910):
let me know if you can do this part at all
jimthompson5910 (jim_thompson5910):
or tell me if you're completely stuck with everything
OpenStudy (anonymous):
I'm so lost...
OpenStudy (anonymous):
He has 4 one dollar bills, two five dollar bills and two ten dollar bills..
If he picks two bills...
What are all the possibilities..
\[\frac{ 8! }{ 4!2!2! }\]
There is the 4! because we have a repeat of dollar bills and 2!'s for the two fives and two tens.
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jimthompson5910 (jim_thompson5910):
ok can you tell me how many bills there are total?
jimthompson5910 (jim_thompson5910):
still stuck? or did you figure it out?
OpenStudy (anonymous):
Sorry I get side tracked a lot i'm trying to focus hold on
jimthompson5910 (jim_thompson5910):
you're ok, take all the time you need
OpenStudy (anonymous):
$34 is total and bills in total are 8 right?
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jimthompson5910 (jim_thompson5910):
yep there are 8 bills in total
jimthompson5910 (jim_thompson5910):
of these 8 bills, how many are tens?
OpenStudy (anonymous):
2, I'm sorry dyslexia and math don't go together
jimthompson5910 (jim_thompson5910):
that's ok, keep at it and you'll get better
jimthompson5910 (jim_thompson5910):
so the probability of picking a ten is 2/8 = 1/4
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OpenStudy (anonymous):
Okay. I get that.
jimthompson5910 (jim_thompson5910):
once you pick out a ten, you'll have 8 - 1 = 7 bills left over
OpenStudy (anonymous):
Otay..
jimthompson5910 (jim_thompson5910):
now how many one dollar bills are there
OpenStudy (anonymous):
4
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jimthompson5910 (jim_thompson5910):
so the probability of picking out a one dollar bill is 4/7 (this is after you picked a ten first)
jimthompson5910 (jim_thompson5910):
you then multiply it with 1/5 to get
(1/5)*(4/7) = (1*4)/(5*7) = 4/35
jimthompson5910 (jim_thompson5910):
so the probability of picking a ten, then picking a one is 4/35
jimthompson5910 (jim_thompson5910):
make sense?
OpenStudy (anonymous):
no....whered the 35 come from?
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jimthompson5910 (jim_thompson5910):
5*7 = 35
jimthompson5910 (jim_thompson5910):
oh wait, sorry
jimthompson5910 (jim_thompson5910):
mixed up numbers, my bad
jimthompson5910 (jim_thompson5910):
it should be
(1/4)*(4/7) = (1*4)/(4*7) = 4/28 = 1/7
jimthompson5910 (jim_thompson5910):
so the final answer is 1/7
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OpenStudy (anonymous):
Omg with my mind doing sifferent stuff it's so hard to concentrate... Idk how i'm gonna pass..
jimthompson5910 (jim_thompson5910):
go through this whole thing again and let me know if you have any questions
jimthompson5910 (jim_thompson5910):
you saw how I got 1/4 for the first part right?
OpenStudy (anonymous):
Ugh x-x no :(
jimthompson5910 (jim_thompson5910):
ok just say so and I'll go over it again
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jimthompson5910 (jim_thompson5910):
there are 8 bills total
there are 2 bills that are tens
so the probability of picking a ten is 2/8 = 1/4
with me so far?
OpenStudy (anonymous):
Yes.
jimthompson5910 (jim_thompson5910):
ok great
jimthompson5910 (jim_thompson5910):
once you pick a bill on the first selection, there are 8 - 1 = 7 bills left over
there are 4 one dollar bills, out of 7 total (leftover), so the probability of selecting a one dollar bill on the next draw is 4/7
still making sense?
OpenStudy (anonymous):
Yush
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jimthompson5910 (jim_thompson5910):
ok good
jimthompson5910 (jim_thompson5910):
you then multiply the two fractions: 1/4 and 4/7
jimthompson5910 (jim_thompson5910):
(1/4)*(4/7) = (1*4)/(4*7)
(1/4)*(4/7) = 4/28
(1/4)*(4/7) = 1/7
still with me?
OpenStudy (anonymous):
yuss
jimthompson5910 (jim_thompson5910):
ok so that's the final answer because you just multiply the two probabilities
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OpenStudy (anonymous):
so the answer is 1/7?
jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
umm okay...
jimthompson5910 (jim_thompson5910):
where are you stuck
OpenStudy (anonymous):
No where it's fine
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