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Mathematics 13 Online
OpenStudy (anonymous):

Two factory plants are making TV panels. Yesterday, Plant A produced 3000 fewer panels than Plant B did. Three percent of the panels from Plant A and 5% of the panels from Plant B were defective. How many panels did Plant A produce, if the two plants together produced 1270 defective panels?

OpenStudy (theeric):

Hi! It looks like you'll have to solve this like a "system of equations." Pretty much, you have panels from Plant A and panels from Plant B, and you want to know how many panels came from each. So the technique is \(\rightarrow\) get all of your information into math form, and use variables for what you don't know. You don't know the numbers of panels. I'll say.. \(\rightarrow\) You have \(a\) Plant A panels \(\rightarrow\) You have \(b\) Plant B panels. Seems reasonable to me!

OpenStudy (theeric):

You have a ton of information. We can go sentence by sentence, though. Keep in mind that \(a\) is the number of Plant A panels and \(b\) is the number of Plant B panels.

OpenStudy (theeric):

"Yesterday, Plant A produced 3000 fewer panels than Plant B did." So, You have \(a\) panels, that were \(3,000\) panels less than \(b\) panels. "Were" means they "were" equal. \(a=b-3,000\)

OpenStudy (theeric):

"Three percent of the panels from Plant A ... were defective." So, 3% of \(a\) was the number of defective panels. Since \(3\%=.03\), there were \(.03\ a\) defective panels from Plant A

OpenStudy (theeric):

"... 5% of the panels from Plant B were defective." Similarly to before, \(5\%=.05\) so \(.05\ b\) is the number of defective panels from Plant B.

OpenStudy (theeric):

"... the two plants together produced 1270 defective panels." We can start putting things together now. So, the defective panels from Plant A plus the defective panels from Plant B equals \(1,270\). Well, we have values for \(\text{defective panels from Plant A}\) and \(\text{defective panels from Plant B}\). They are \(.03\ a\) and \(.05\ b\) respectively, and they add up to \(1,270\). Put into math speak, that's \(.03\ a+.05\ b=1,270\) And we know from before that \(a=b−3,000 \). Now you have a couple equations.\[.03\ a+.05\ b=1,270\]\[a=b−3,000 \]

OpenStudy (theeric):

Now you can solve for \(a\) in one equation, and substitute that into the other equation. After you do that, you can solve for \(b\). It will be the only variable. So then you'll know what \(b\) is! And, if you know what \(b\) is, you can substitute its value in to the equation in which you solved for \(a\). By doing that, you'll find the value of \(a\). That's the method for solving systems of equations. Solve for things, use substitution wisely, and keep on solving, calculating, and substituting until you find all your variables.

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