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@MayMay_69, what is the definition of a rhombus?
Well it's more than just that...something very specific about a rhombus.
sorry .. yep you are right. So besides proving it is a rhombus by showing that the diagonals are perpendicular bisectors of each other...how else could you prove the shape is a rhombus.
Well if a rhombus is EQUIlateral what does that mean about the sides?
@MayMay_69 I see coordinates...in the original problem.
Well which way will be quicker, which will require less work?
What do you mean? You could determine if the diagonals are perpendicular bisectors using the slope formula to test for perpendicularity and the midpoint formula to test if they bisect each other OR you could use the distance formula to measure the distance between consecutive vertices to determine if all of the sides are equal in length. Which way would be better?
Ok why?
Well there is your answer, but I would be more specific than "because" ...I don't think there is a wrong answer, but you should be able to explain your reasoning.
Well some people might not think so. I mean to use the distance formula you have to do it 4 times once for each side but for the other method all you have to do is find the two slopes and verify that the midpoints of the diagonals are the same place. Some would say that is easier. I guess it depends how comfortable you feel with the distance formula and square roots versus how comfortable you feel with fractions and the slope and midpoint formulas.
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