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OpenStudy (anonymous):
OpenStudy (mathmate):
Blue:
Denote tension in cord as T. Vertical reaction on bar equals weight of bar, assuming no friction anywhere.
Take moments about B. Solve for T.
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
can you show to me
OpenStudy (mathmate):
"How" meaning to take moments?
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OpenStudy (anonymous):
yes but i'm confuse >.<
OpenStudy (anonymous):
roller gve vertical force to the wall so therefore
OpenStudy (anonymous):
|dw:1375615728179:dw|
OpenStudy (anonymous):
|dw:1375615816627:dw|
OpenStudy (anonymous):
also
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OpenStudy (mathmate):
I can give an example:
|dw:1375616654183:dw|
A ladder 5 m long leans agains a smooth wall at B and stands on a rough floor at A at a distance of 3 m from the wall as shown above. The mass of the ladder is 10 kg.
Since we don't know the friction on the floor, we can take moments about A so the friction does not come in the equation.
Let reaction at B = R
Mass at the middle (C) = m
Take moments about A, since the ladder is in equilibrium, sum of moments = 0.
-R*4 + mg*(3/2)=0
Note: moment = force * distance, clockwise is positive.
Solve for R:
R=(3mg/2)/4, or =3mg/8 N.
OpenStudy (mathmate):
|dw:1375617070605:dw|
OpenStudy (anonymous):
yes u are right
OpenStudy (mathmate):
So you're good for both problems?
OpenStudy (anonymous):
no
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