an explanation please:
U(x)=−∫F(x)dx+C find F(x). according to my book it should be done this way but I dont understand the logic behind it. ddx∫F(x)dx=F(x) F(x)=−dU(x)dx
original question: http://openstudy.com/users/bronzegoddess#/updates/51fad2f4e4b0259e2c33bd2b
think of it this way, the integral is the opposite of a derivative so combining an integral with derivative with respect to the same variable will cancel each other out
what ended up happening for your problem is, the derivative with respect to x was taken on both sides then f(x) was solved the constant "C" disappears because the derivative of a constant is zero
Given that U(x) = - ∫F(x)dx + C, then - U(x) = ∫F(x)dx + C [1] (the sign of C does not change, as C may be anything). The differential of an integral is equal to the function that was being integrated, but without any constant, as the differential of a constant is 0. So d/dx (∫F(x)dx + C) = F(x) [2]. Now substituting [1] into [2] gives F(x) = -dU(x)/dx.
thank you both, i wish i could give two medals but incognito was more specific :/
You're welcome :)
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