Question

Solve tan(x)(tanx + 1) = 0 .

Answer 1

Well, this is already given to you in factored form. When you have everything in factored form, you can take each factor and set them each to 0 independent of one another. So I could say
tanx = 0
tanx + 1 = 0
And then solve for x in both.

Answer 2

the first is πn

Answer 3

That's one of the two answers for the first one, unless you can't include 0.

Answer 4

the next is x = 1/4 (4πn - π)

Answer 5

Works for me :3

Answer 6

would that mean its x = πn, and x = π/4 plus or minus nπ?

Answer 7

wait, am I wrong @Psymon ?

Answer 8

@cambrige @abb0t was I wrong?

x = πn, and x = π/4 plus or minus nπ

Answer 9

Well, all values where tanx= -1. So 3pi/4 + kpi

Answer 10

And then for tanx = 0, itd be 0 + kpi

Answer 11

Can ya see why?

Answer 12

not really?

x = 3π/4 plus or minus 2πn

Answer 13

Alrighty, hang on.

Answer 14

So those are the 4 values. The period of the tangent function is pi, so you would just add kpi to each of those.