Question

What is the slope of a line that passes through the point (−1, 1) and is parallel to a line that passes through (4, 6) and (−1, −4)?

Answer 1

First find the slope of the line that passes through the point (4,6) and (-1,-4)

use this \[m = \frac{y2-y1}{x2-x1}\]

Answer 2

-7/-5 @mebs

Answer 3

No, not quite... do this \[m = \frac{ 6 - (-4) }{ 4 - (-1) }\]

Answer 4

10/5 @mebs

Answer 5

2 @mebs

Answer 6

yes so now we have a slope m = 2

we can use this \[y - 1 = 2(x +1)\]

solve for y

Answer 7

2x+3

Answer 8

In general you have a point (-1,1) which is (xo , yo)

\[y - yo = m (x - xo)\]

yes you are correct @snewton29

y = 2x +3

Answer 9

So the answer is 2x+3 for my whole answer
@mebs

Answer 10

No. the slope is 2. that is your whole answer.

Answer 11

New question ,
What is the value of x in the solution to the following system of equations
X-Y=-3
X+3Y=5

Answer 12

@mebs

Answer 13

y = x +3

sub that into x +3y = 5

solve

x + 3(x+3) = 5

Answer 14

I have to go. @cambrige take over.

Answer 15

How would u solve that @cambrige

Answer 16

yup
m here

Answer 17

Just remember..slope of two parallel lines always equal...
and slope of 2 perpendicular lines -ve multiplicative inverse!!

Answer 18

so for example if slope of a line is m=3,
slope of a line parallel to it m'=3
sope of a line perpendicular to it m"=-(1/3)

Answer 19

In answer 2 ur second Q,
U can use wat @mebs mentioned known as
1.substitution method or
2.elimination method

Answer 20

In sub method use any one of the equations to obtain the value of one(say x) of the two variables in terms of the other.
Substitute this value in the second linear eq. to get value of that variable(say x).
the use any eq and substitute value of variable(here x) to get the variable of y!!

Answer 21

Tell me wen u r online I'll xplain u the 2nd method!!Cheers!!