Question

- tan ^ 2 x+ sec ^2 x = 1

Answer 1

\(\bf sec^2(x)-tan^2(x) \implies \cfrac{1}{cos^2(x)}-\cfrac{sin^2(x)}{cos^2(x)} \implies \cfrac{1-sin^2(x)}{cos^2(x)}\)

check your trig identities to see what \(\bf 1-sin^2(x)\) is

Answer 2

Its negative tan though

Answer 3

\(\bf -tan^2(x)+sec^2(x)=1 \implies sec^2(x)-tan^2(x)\)

Answer 4

Ok so it flips places

Answer 5

well, yes, I used that, but yes, I commute it :)

Answer 6

Ok would 1-sin ^2 (x) = cos x

Answer 7

well \(\bf sin^2(\theta)+cos^2(\theta)=1\)
if you solve for \(\bf cos^2(\theta)\)
what do you get?

Answer 8

I don't know

Answer 9

how about this one
a + b = 1

if you solve for "b", what do you get?

Answer 10

0

Answer 11

0?

Answer 12

Yeah

Answer 13

u still here

Answer 14

yes

Answer 15

Ok well could u still guide me through this ?

Answer 16

well, there's no much there really, you see
\(\bf sin^2(\theta)+cos^2(\theta)=1\)
then see what you get if you were to solve for \(\bf cos^2(\theta)\)

Answer 17

What do you mean ? Would I subtract cos from both sides? I am brain farting right now

Answer 18

well, to isolate \(\bf cos^2(\theta)\)
you'd need to substract \(\bf sin^2(\theta)\) from both sides

Answer 19

Ok wow so would \[\cos ^{2}(\theta) = 1 - \sin ^{2} (\theta)\] be the answer