How do you prepare 250 mL of a 0.500 M NaOH solution from a 6.00 M NaOH solution?

Question

aaronq · Answer

$$M _{1}V _{1}=M _{2}V _{2}$$

aaronq · Answer

you would first find the volume of stock you need, then dilute that to the given volume.

anonymous · Answer

Hello! Thank you for answering; the problem is that I don't know how to go about setting these types of molarity questions up to get to the final answer

aaronq · Answer

so you have one set of conditions 

we assign that set as (1) arbitrarily: 250 mL of a 0.500 M NaOH

set (2): 6.00 M NaOH, V=? 

we need to find the volume of stock solution that contains the necessary moles asked for in the question.

so we make them equal to each other:

(0.250 L)*(0.500 M)=(6 M)*V2

algebraically, solve for V2

anonymous · Answer

And by solving for V2, we'll find what?

aaronq · Answer

V stands for volume

anonymous · Answer

Oh just kidding! I see what you did

aaronq · Answer

when you divide the Molarity units will cancel out

anonymous · Answer

Oh good! Okay, I think I can figure this out from here. Thank you!

aaronq · Answer

good stuff, no problem !