Question

Alan is twice as old as sue and half as old as Joseph. If the average of all three ages is 14, how old is sue?

Answer 1

This is a strange age-problem :3

But, a word problem nonetheless... the first step in solving word problems is representing values...
If we let x be the age of Sue, what is the age of Alan?

Answer 2

2x

Answer 3

And Joseph is 1/2x ?

Answer 4

No... Alan's age is 2x, yes, and Alan's age is HALF of Joseph's age...
So Joseph must be older... so it's not \(\Large \frac12x\) :P

Answer 5

S Joseph age is 1/2(2x)

Answer 6

No. Look, let's say Joseph's age is j.
And Alan's age, which is 2x is half of j.
\[\Large 2x = \frac12j\]
So what is j in terms of x?

Answer 7

4x=j

Answer 8

Better :P
So Joseph's age is 4x.

Sue = x
Alan = 2x
Joseph = 4x

What's their average?

Answer 9

14

Answer 10

Yeah, but how do you represent their average?

Answer 11

X+2x+4x/3=14

Answer 12

Very good :)
\[\Large \frac{x+2x+4x}{3}=14\]
can you solve for x?

Answer 13

X=6

Answer 14

And that's Sue's age :D
Remember, we let Sue's age be x

Good job ^_^

Answer 15

Ty metal for you

Answer 16

I hate word problems

Answer 17

Well, they're not gonna love you either way, so you better learn how to DEAL WITH THEM.

LOL

Signing off now
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Terence out