Question

Find sin Θ if tan Θ= the square root of 2 and falls in Quadrant 3. HELP PLEASE ASAP
@robtobey @radar

Answer 1

tan (theta) = sqrt(2) = sqrt(2) / 1
Recall that tan (theta) = y/x
and sin (theta) = y/r
In this case, opposite side = sqrt (2) and adjacent side is 1.
The fact that theta is in quadrant 3 also implys that both x and y values are negative
Thus x = -1 and y = -sqrt(2)
Now simply use Pythagorean theorem to calculate r and write out x/r for sin(theta)

Answer 2

so the answer is -1/-sqrt(2) ? @CLOUDYskies

Answer 3

Use the Pythagorean Theorem to find the hypotenuse.