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Mathematics 15 Online
OpenStudy (bambimonster):

see atttachment

OpenStudy (bambimonster):

OpenStudy (bambimonster):

thanks how about the second question?

OpenStudy (anonymous):

Lol crap, accidentally deleted it. iPad. Anyways, the second question seems to be based on the assumption that the first one is possible.

OpenStudy (bambimonster):

i got the answer 0.0418

OpenStudy (anonymous):

Lol in that case I seem to be quite mistaken in my assumption. I shoul dorovably review that a bit more before I answer next time.

OpenStudy (bambimonster):

like idk if its correct tho.. i havent submitted it yet.. so im asking if its correct

OpenStudy (anonymous):

How exactly did you arrive at that answer, though? From what I'm seeing right now, this looks similar to a student distribution problem.

OpenStudy (anonymous):

Although the fact that the question stated "some right skewed distribution" is still kind of bothering me.

OpenStudy (bambimonster):

7.62-6.66/3.29\[\div \sqrt{3}\]

OpenStudy (bambimonster):

*\[\sqrt{35}\]

OpenStudy (bambimonster):

z=1.7262

OpenStudy (anonymous):

I don't believe the question stated that this was a normal distribution. Doesn't the Z table only work with distributions that are normal?

OpenStudy (bambimonster):

hmm true... im confused myself.. its okay i ll figure it out tmrw.. thanks anyway :)

OpenStudy (anonymous):

No problem, this served as good review for myself as well. I'm sorry that I couldn't be of more use, though.

OpenStudy (anonymous):

Okay, I discussed the question with a few friends of mine, and we reached the agreement that according the Central Limit Theorem, with a distribution that has more than 30 entries, the skewed distribution can be approximated as a normal one, meaning what you did there for part b should be correct. Since part A only has 3 entries considered, the same cannot be applied to that, which means the answer should still be not possible .

OpenStudy (bambimonster):

@CLOUDYskies thanks :)

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