Juan invested his savings in two investment funds. The$8000 that he invested in Fund A returned a 1% profit. The amount that he invested in Fund B returned a 5% profit. How much did he invest in Fund B, if both funds together returned a 4% profit?
@hero this is the new question they gave me
a = Fund A = 8000 b = Fund B c = Total Amount invested Juan invested 8000 in fund a so: 8000 + b = c This is the profit equation. He gets a 1% profit return on the 8000 invested in fund a. He gets 5% for fund b, and together he receives 4% profit on the total investment: .01(8000) + .05b = .04(c)
So you have to solve this system: 8000 + b = c .01(8000) + .05b = .04c Remember: \(1\% = \frac{1}{100} = .01\) \(5\% = \frac{5}{100} = .05\)
I got b=-1599.2 is that correct
Nothing will be negative. You can't invest negative money.
Try to understand the equations first.
6400.8
when I solve for .01(8000) + .05b = .04c it gives me a negative number
This is a systems of equations. You have to solve both equations together.
im not sure what to do im really confused
Have you ever solved a system of equations before?
yes the way your telling me to do it Im getting a negative number
I Solve for b first using .01(8000) + .05b = .04c then I sub B into 8000 + b = c correct
I haven't told you to do anything yet. I just set up the system. You started doing your own thing.
What is 1% of 8000?
That's the same as asking you to simplify .01(8000)
80
Good. We were able to get that far....so now we have 8000 + b = c 80 + .05b = .04c
Now, multiply both sides of the second equation by 100
100(80+.05)=100(.04) correct?
b=0.8c-1600 c=1.25b+2000
What have you done now? I said to multiply both sides of the second equation by 100, which you did, but you removed the variables...WHY?
100(80+.05)=100(.04) <---- not correct 100(80 + .05b) = 100(.04c) <--- is correct
b=1/2000c-0.0006
You're doing your own thing again...
Either that or you don't know how to simplify the equation after multiplying both sides by 1000.
I don't know how to
I keep coming up with the wrong answer so I don't know what I am doing
After multiplying both sides by 100 you get 100(80 + .05b) = 100(.04c) After simplification you get 8000 + 5b = 4c
That is still the second equation
If we put both equations back together again we have 8000 + b = c 8000 + 5b = 4c
The next thing to do is use substitution since: c = 8000 + b Substitute 8000 + b in place of c in the second equation
Can you do that?
am i solving for b
Go back to the original question to find out what you're solving for.
24000
Wow...
You actually got it
lol
thank you so much
I see what you were trying to do earlier now. You're solving for b, however, you have to first figure out if you plan to use elimination or substitution to solve the system. If you use elimination, you have to make sure you eliminate variable c. If you use substitution, you have to make sure the final equation you solve is in terms of variable b.
yes I was very confused on what to do but thank you @hero
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