Question

sin^5x
integrate

Answer 1

@Tutor.Stacey

Answer 2

sin^5x=(sinx)^4 *sinx
=((sinx)^2)^2 *sinx
=(1-cos^2x)^2*sinx
now take cosx = t and proceed

Answer 3

we will use integration by parts ... anyway was just checking on you guys out here.

Answer 4

no not necessary expand the binomial instead and then simply integrate

Answer 5

you can do that to

Answer 6

(1-cos^2x)^2*sinx dx after substituting cosx=t -sinx dx =dt
it becomes
-(1-t^2)^2 dt
i hope i need not do further

Answer 7

Remeber of odd powers for sinx or cosx u have to do similarly as above
but for even powers of sinx or cosx u have to express everything in terms of cos2 x or cos4x etc as the case may be

Answer 8

for e.g
sin^2x= 1/2 (1-cos2x)
cos^2x=1/2 (1+cos2x)

Answer 9

sin^2 2x= 1/2 (1-cos4x)
cos^2 2x=1/2 (1+cos4x)