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OpenStudy (anonymous):
\[-\frac{2}{3}x=\frac{3}{10}\] like that?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
solve in one step via
\[x=\frac{3}{10}\times \left(-\frac{3}{2}\right)\]
OpenStudy (anonymous):
oh!! i was flipping the wrong fraction. i flipped the 3/10 and left the -2/3
OpenStudy (anonymous):
yeah flip the coefficient of the \(x\) term
leave the number on the other side alone
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OpenStudy (anonymous):
I'm still getting the wrong answer when I try to check it :(
OpenStudy (anonymous):
I'm sorry its -2/5x=3/10. Let me try to solve it now....
OpenStudy (anonymous):
ok let me know what you get and i will check your answer
OpenStudy (anonymous):
i got 3/4
OpenStudy (anonymous):
\[\frac{3}{10}\times \left(-\frac{5}{2}\right)\]
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OpenStudy (anonymous):
don't forget the \(-\) sign
OpenStudy (anonymous):
oo yea... thank you.. i always forget the sign
OpenStudy (anonymous):
don't want to do that
instead of getting \(+5\) pts on the test you get \(-5\) pts
OpenStudy (anonymous):
LOL.. thank you.. i have another one if u dont mind
OpenStudy (anonymous):
go ahead
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OpenStudy (anonymous):
(y-3)-(y+3)=6y
OpenStudy (anonymous):
(-3y)-(3y)=6y?
OpenStudy (anonymous):
remove parentheses on the left, and get
\[y-3-y-3=6y\]
OpenStudy (anonymous):
no no, \(y-3\) is not \(-3y\) just like \(5-3\) is not \(-3\times 5\)
OpenStudy (anonymous):
lets go slow
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OpenStudy (anonymous):
this is your equation
\[\large (y-3)-(y+3)=6y\] right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok now for that minus sign, before can combine like terms you have to remove the parentheses on the left, and make sure to use the distributive law
\[\large y-3-y-3=6y\]
OpenStudy (anonymous):
why did u change the + 3 to - 3?
OpenStudy (anonymous):
is it clear how i got that from \((y-3)-(y+3)=6y\) ?
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OpenStudy (anonymous):
good question
it is the distributive law
OpenStudy (anonymous):
\[-(y+3)=-y-3\]
OpenStudy (anonymous):
oooo yea.. - times y and - times 3
OpenStudy (anonymous):
or if this makes it easier
\[\large \color{red}{-1}(y+3)=\color{red}{-1}y+\color{red}{-1}\times 3=\color{red}-y\color{red}-3\]\]
OpenStudy (anonymous):
ok got it..
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OpenStudy (anonymous):
so now on the left you have
\[y-3-y-3\] and you have to combine like terms
OpenStudy (anonymous):
you know what you get?
OpenStudy (anonymous):
I'm still getting -6y=6y :(
OpenStudy (anonymous):
ok close
OpenStudy (anonymous):
Because the y's cancel.. then -3-3 is -6
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OpenStudy (anonymous):
you have \[y-3-y-3\] lets rearrange as
\[y-y-3-3\]
OpenStudy (anonymous):
ahh ok. yes you are right, but it is not
\[-6y=6y\] you just said the \(y\)'s cancel (add up to zero) and also \(-3-3=-6\) so the equation is actually
\[-6=6y\]
OpenStudy (anonymous):
see the difference? not \(-6y=6y\) but rather \(-6=6y\)
OpenStudy (anonymous):
oh yea that's what I meant.. See my problem is rushing through it.. I'm always on the right path but I end up putting something where it's not supposed to be or forgetting my signs. I definitely need to work on that
OpenStudy (anonymous):
so the answer is -1
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OpenStudy (anonymous):
yes, all of this requires being careful
the problem is, if you make one small error, you cannot fix it, you are wrong from there on in
yes, the answer is \(-1\)
OpenStudy (anonymous):
got more or are you done?
OpenStudy (anonymous):
I have more but I don't want to take up all your time.. do you mind?
OpenStudy (anonymous):
no go ahead we can do a couple more
OpenStudy (anonymous):
ok :)
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OpenStudy (anonymous):
1/6x=-7
I flipped changed it to 6/1 times -7/1
OpenStudy (anonymous):
yes
what did you get ?
OpenStudy (anonymous):
-42/1
or should I cross multiply?
OpenStudy (anonymous):
no do not "cross multiply" whatever that means
your answer is \(-\frac{42}{1}\) but if you write that your teacher will think you are not paying attention
just write \(-42\)
OpenStudy (anonymous):
in other words, solve
\[\frac{1}{6}x=-7\] by
\[x=-7\times 6=-42\]no need for the ones
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OpenStudy (anonymous):
yea that's what i left it as -42 :)
OpenStudy (anonymous):
got it!
more?
OpenStudy (anonymous):
the ones kind of help me during the multiplication process but I remove it once i'm get my answer.
OpenStudy (anonymous):
then use it if it helps
OpenStudy (anonymous):
1/5f-5=1
solve the equation by first clearing the fraction..
i'm thinking of changing the fraction into a decimal
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