Question

Eliminate the parameter.

x = t2 + 2, y = t2 - 4

Answer 1

@phii

Answer 2

@phi

Answer 3

@thomaster

Answer 4

y = x - 6, x ≥ 1

y = x + 6, x ≥ 1

y = x2 - 6, x ≥ 1

y = x2 + 6, x ≥ 1

Answer 5

\[\begin{cases}x=t^2+2\\y=t^2-4\end{cases}\]
Since both \(x\) and \(y\) contain \(t^2\), I suggest solving one for \(t^2\), then substituting that into the other equation.

Answer 6

\[x=t^2+2~\Rightarrow~t^2=x-2\]
So, you have \[y=(x-2)-4\]

Answer 7

y = x - 6

Answer 8

Yup

Answer 9

so its a?
you rock