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Mathematics 16 Online
OpenStudy (anonymous):

Find a cubic function with the given zeros. √6, -√6, -3

OpenStudy (zzr0ck3r):

(x-a)(x-b)(x-c) is a cubic function with zeros at a,b,c so can you answer this?

OpenStudy (anonymous):

No

OpenStudy (zzr0ck3r):

if the question said Find a cubic function with the given zeros. a, b, c then the answer would be (x-a)(x-b)(x-c) now?

OpenStudy (anonymous):

You have to just plug in a,b,c a=√6, b= -√6,c= -3

OpenStudy (anonymous):

then distribute to get the original equation.

OpenStudy (amistre64):

distributing is not required unless they ask for that type of format

OpenStudy (amistre64):

f(x) = (x-a)(x-b)(x-c) is still a cubic function with the given roots

OpenStudy (anonymous):

well then its even easier! just plug in the values for a,b,c

OpenStudy (amistre64):

:)

OpenStudy (amistre64):

the factored form, i believe is called the intercept form .. since its constructed from the intercepts

OpenStudy (anonymous):

well lets say the given zeros where 1, 2, 3 --- (x-a)(x-b)(x-c) is a cubic function with zeros at a,b,c so can you answer this? --- then (x-1)(x-2)(x-3) we just plug in. Can you plug in your numbers?

OpenStudy (anonymous):

f(x) = x3 - 3x2 - 6x - 18 ? @timo86m

OpenStudy (anonymous):

let me dbl check you got (x-a)(x-b)(x-c) Plug in √6, -√6, -3 (x-(sqrt(6))(x-(-sqrt(6)))(x-(-3)) then expand :)

OpenStudy (anonymous):

thank youu (:

OpenStudy (anonymous):

x^3+3 x^2-6 x-18

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