Let h = ((v0^2)/4.9) sinθcosθ model the horizontal distance in meters traveled by a projectile. If the initial velocity is 44 meters/second, which equation would you use to find the angle needed to travel 150 meters?

Question

Let h = ((v0^2)/4.9) sinθcosθ  model the horizontal distance in meters traveled by a projectile. If the initial velocity is 44 meters/second, which equation would you use to find the angle needed to travel 150 meters?

anonymous · Answer

h = ((v(subscript o)^2)/4.9) sinθcosθ

phi · Answer

is this multiple choice or can do you just write down an equation ?

anonymous · Answer

A.	395.10sin(2θ) = 150
 		B.	150sin(2θ) = 150
 		C.	8.98sin(2θ) = 150
 		D.	197.55sin(2θ) = 150

phi · Answer

to do this problem you need to know
$$ 2 \sin(\theta) \cos(\theta)=  \sin(2\theta) $$
if you divide both sides by 2, this is the same as
$$\sin(\theta) \cos(\theta)= \frac{1}{2} \sin(2\theta) $$

anonymous · Answer

I was thinking	C.	8.98sin(2θ) = 150

phi · Answer

the way to do it is start with
$$  \frac{v_0^2}{4.9} \sinθ\cosθ = h$$
now use the identity posted up above to replace sinθ cosθ
also, replace v0 with 44
can you do that ?

anonymous · Answer

Oh.. Damn okay! Nevermind then. I got D now