what is the factorization of -x2+2x+48

Question

anonymous · Answer

What are two numbers tat multiply to -48 and add up to 2?

anonymous · Answer

that*

anonymous · Answer

8,6

anonymous · Answer

is it (-x+6)(x+6)

anonymous · Answer

So you'll need something like:$$(-x \pm 8)(x\pm 6).$$You just have to figure out if its a plus or minus that goes in each one.

uri · Answer

-x2+2x+48
-x^2+8x-6x+48
-x(x+8)-6(x+8)
(-x-6)(x+8)

anonymous · Answer

Since you want a positive 2x, I suggest trying:$$(-x+8)(x+6)$$

campbell_st · Answer

@uri... your epansion gives the coefficient of x as -14

uri · Answer

How? +8-6=2

anonymous · Answer

when you factor say $$-x^2+8x$$it becomes:$$-x(x-8)$$

campbell_st · Answer

@uri (-x -6)(x +8) is your solution...

anonymous · Answer

you have -x(x+8).  Same with the right side, your missing a negative.

uri · Answer

Oh yeah..blurry sorry typo..
It is..
(-x-6)(x-8)

uri · Answer

2 a.m...I need my glasses xD

campbell_st · Answer

most people are happy factoring when the leading term is positive. So a simple method is the take -1 as a common factor... 

$$-1(x^2 -2x - 48)$$

now look at the quadratic you need to factor... and use the information above.

mathstudent55 · Answer

I suggest you first factor out -1:
$-x^2+2x+48$

$ = -1(x^2- 2x-48) $

Now you need 2 fators of -48 that add to -2: -8 and 6

$= -1(x -8)(x + 6) $

Now if you'd like, you can multiply the -1 back in:

$= (-x + 8)(x + 6) $