Ask
your own question, for FREE!
Mathematics
12 Online
OpenStudy (anonymous):
[7.02] Choose the correct simplification of (4x + 7) + (2x − 3).
6x + 4 <---- Is this the correct answer?
6x + 10
6x − 4
10x
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
you are correct
OpenStudy (anonymous):
Cool can you help me with a few other problems?
jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
[7.03] Choose the correct simplification of (x9)2.
x11
x7
x81
x18 < This is the correct answer right?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
9 and 2 are exponents?
OpenStudy (anonymous):
Yes. Sorry about that
jimthompson5910 (jim_thompson5910):
that's ok
jimthompson5910 (jim_thompson5910):
you are correct
OpenStudy (anonymous):
[7.01] Choose the polynomial written in standard form.
5x3 + 17x5 − 6x4 + 10x4x2 + x2y + 2
3x3 + x5 − 3
x3y2 + xy2 − 1
2x + x2 − 9
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I don't know the answer to this one
jimthompson5910 (jim_thompson5910):
hint: standard form will have the exponents going in decreasing order
OpenStudy (anonymous):
standard form means decreases exponent
OpenStudy (anonymous):
decreasing or descending order.
OpenStudy (anonymous):
So it is \[x ^{3} y ^{2} + xy ^{2} − 1\]?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
one more question
jimthompson5910 (jim_thompson5910):
go for it
OpenStudy (anonymous):
[7.04] Choose the correct simplification of x to the 8th power over x to the 3rd power.
x11
1 over x to the 5th power
x24
x5
OpenStudy (anonymous):
is it \[x ^{5}\] ?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
good, you nailed it
OpenStudy (anonymous):
Thank you so much! You really helped me out!
jimthompson5910 (jim_thompson5910):
I'm glad I did, yw
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!