factor 16x2+40x+25 in polynomial descending order
What did you get for this one?
i dont get it
Alright, something to look for when you see this type of problem. Notice that the first term (16x^2) is a perfect square, and the last term (25) is also a perfect square.
5
This means you're probably going to have something like this: \[(a+b)^2 or (a-b)^2 \]
Yeah. In this case, when you factor, just take the square root of 16x^2 and the square root of 25. Tell me what you get for each.
(16x+5)(x+5)
Wait wait. Just take the square root of 16x^2 and take the square root of 25. What do you get?
20
Oh god. Lol.
Erm, you told me the square root of 25 is 5, right? What is the square root of 16x^2?
I think she/he is searching it up on google.
4
Lol, that would also be a way to go.
4^2 gives 16, so you're looking for 4x. (4x)(4x)=16x^2
So 4x is the square root of the first term, and 5 is the square root of the second term. Our answer is just \[(4x+5)^2\]
Nifty, eh?
Hmm, what about 40x?
Good question. Now this part is really important. If we have a suspicion that our answer is \[(4x+5)^2\]we have to check it by using FOIL. We get \[(4x+5)^2=(4x+5)(4x+5)=16x^2+20x+20x+25=16x^2+40x+25\]
I just wanted the kid to see the foil method. Lol.
Oh, lol. Sorry, I thought that was him responding. That's where we were going next anyway. I wasn't going to let him try to use the square of a binomial with just anything that happened to have perfect squares for the first and last terms.
Good explaining. Keep it up!
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