find the vertical asymptotes, if any, of the graph of the following rational function. f(x)=x/x^2+8... i do not understand this. please explain how to solve this
I'm assuming the denominator is x^2 + 8 correct?
or is it just x^2 ?
assuming x^2+8 is the denominator, this would mean that if x^2 + 8 was zero, then x^2 + 8 = 0 x^2 = -8 x = sqrt(-8) since taking the square root of a negative number gives you a complex/imaginary number, this means that there are no real solutions to x^2 + 8 = 0
what this means is that x/(x^2 + 8) will have no real values of x which make the denominator zero so you don't have to worry about division by zero errors and that means there are no vertical asymptotes
thank you so much! lol ten more ?s to go! god this stuff confuses me lol
you're welcome
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