Question

if \(\sqrt{a}=c\sqrt{d}\) and \(\sqrt{b}=d\sqrt{c}\) then find \(\sqrt{a^2b^4}\) in terms of \(c\) and \(d\)

Answer 1

jeez c'mon

Answer 2

know i know what it is like to ask a question here
c'mon what do you get?

Answer 3

would it help to say that i have my answer, and i would like it checked?

Answer 4

Please show your work. It is against CoC to give answers.

Answer 5

lol

Answer 6

:)

Answer 7

problem is, i don't get the answers that poor @Big_Booty has in her (his?) choices

Answer 8

thought i would get a second opinion
it is not rocket science (brain surgery, whatever)

Answer 9

you know, I dare not answer, I don't know what's going to pop up if I do

Answer 10

http://assets.openstudy.com/updates/attachments/52006c08e4b05ca78420326b-big_booty-1375759410308-51ffaab3e4b05ca7841ff0a5mary.rojas137570989131726.png

Answer 11

Well \[\sqrt{a^2b^4}=ab^2\]\[a=c^2d\]\[b=d^2c\implies b^2=d^4c^2\]\[ab^2=c^4d^5\]is what I get.

Answer 12

bless you

Answer 13

I agree.

Answer 14

that is what i got as well

Answer 15

so now i don't feel like i screwed up and told @Big_Booty wrong
no correct answer among the choices

Answer 16

Seems like that problem was written terribly.

Answer 17

yes, it does
you want to see a great answer?

Answer 18

It hapens =/ Its always the worst when you are helping someone and there is an error in their problem/text book. Then the person your helping starts to doubt if you are right, an argument can start, and you could start to doubt yourself o.O

Answer 19

I got c4d5 as well

Answer 20

someone asked how to write \(\frac{3}{\sqrt{8}}\) in simplest radical form, which they actually called "exact" form
i said multiply top and bottom by \(\sqrt{2}\) and the teacher wrote back and said

ESSAY FEEDBACK good start here but you don't have the square root of 16 you have square root of 64 and that equals 8.
Then on the top you also need to multiply by square root of 8.
The rule is you can not ever have a fraction with a square root denominator or zero or negative.

Answer 21

still pissing me off
i think i will go get some watermelon and take a break

Answer 22

Reminds me of WebWork for calc 3. It was a good day when all the questions were written correctly.

Answer 23

one thing for over worked underpaid grad students to screw up an routine question, far worse (imho) entirely for a "math teacher" to write that nonsense above

Answer 24

most of ppl would just multiply square root of 8 tho

Answer 25

and later divide by the common multiples and get the same answer u got hahaha

Answer 26

look at this
good start here but you don't have the square root of 16 you have square root of 64
really? did you look at the answer???

Answer 27

thats plain stupidity lol

Answer 28

and then says
Then on the top you also need to multiply by square root of 8.

like you have to believe it to see it!

Answer 29

satellite's teacher

Answer 30

and the final insult
The RULE is you can not ever have a fraction with a square root denominator

Answer 31

that being the answer to why \(\frac{3\sqrt{8}}{8}\) is the EXACT form of \(\frac{3}{\sqrt{8}}\)

Answer 32

ok i will go take my xanax now and relax, maybe chase it with a shot of tulley

Answer 33

i thought u were gonna get watermelon lol

Answer 34

a radical in the denominator is not "elegant" according to math gods and goddesses