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OpenStudy (anonymous):
√h^3/49k^2
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OpenStudy (anonymous):
@ilfy214
OpenStudy (anonymous):
can yu help
OpenStudy (anonymous):
\[\frac{ \sqrt{h}^3 }{ 49 } k^2\]
is this your problem?
OpenStudy (anonymous):
is the square root over the whole thing? as in
\[\large \sqrt{\frac{h^3}{49k^2}}\]
OpenStudy (anonymous):
@ilfy214 its the problem like @satellite73 wrote
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OpenStudy (anonymous):
@satellite73 yes
OpenStudy (anonymous):
Okay, its written like this :)
√(h^3/(49k^2))
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
√1 = 1
√49 = 7
\[\frac{ 1 }{ 7 } \sqrt{\frac{ h^3 }{ k^2 }}\]
OpenStudy (anonymous):
h^(3/2)/(7 k)
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OpenStudy (anonymous):
i thought it was h^(2/3)?
OpenStudy (anonymous):
By itself? Where would the 7k go?
OpenStudy (anonymous):
OH! I see what you mean.. I wrote it wrong on the equation... Hold on!
Alternate form assuming h and k are positive:
OpenStudy (anonymous):
\[\frac{ h ^ \frac{ 3 }{ 2 } }{ 7k }\]
OpenStudy (anonymous):
not to butt in, but
\[\sqrt{49k^2}=7k\] and
\[\sqrt{h^3}=\sqrt{h^2h}=\sqrt{h^2}\sqrt{h}=h\sqrt{h}\]
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OpenStudy (anonymous):
oh ohk how would you simplify that
OpenStudy (anonymous):
@satellite73 just did the rest! :)
OpenStudy (anonymous):
\[\frac{ h√h }{ 7k }\]
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
No prblem!
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