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Mathematics 14 Online
OpenStudy (anonymous):

√h^3/49k^2

OpenStudy (anonymous):

@ilfy214

OpenStudy (anonymous):

can yu help

OpenStudy (anonymous):

\[\frac{ \sqrt{h}^3 }{ 49 } k^2\] is this your problem?

OpenStudy (anonymous):

is the square root over the whole thing? as in \[\large \sqrt{\frac{h^3}{49k^2}}\]

OpenStudy (anonymous):

@ilfy214 its the problem like @satellite73 wrote

OpenStudy (anonymous):

@satellite73 yes

OpenStudy (anonymous):

Okay, its written like this :) √(h^3/(49k^2))

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

√1 = 1 √49 = 7 \[\frac{ 1 }{ 7 } \sqrt{\frac{ h^3 }{ k^2 }}\]

OpenStudy (anonymous):

h^(3/2)/(7 k)

OpenStudy (anonymous):

i thought it was h^(2/3)?

OpenStudy (anonymous):

By itself? Where would the 7k go?

OpenStudy (anonymous):

OH! I see what you mean.. I wrote it wrong on the equation... Hold on! Alternate form assuming h and k are positive:

OpenStudy (anonymous):

\[\frac{ h ^ \frac{ 3 }{ 2 } }{ 7k }\]

OpenStudy (anonymous):

not to butt in, but \[\sqrt{49k^2}=7k\] and \[\sqrt{h^3}=\sqrt{h^2h}=\sqrt{h^2}\sqrt{h}=h\sqrt{h}\]

OpenStudy (anonymous):

oh ohk how would you simplify that

OpenStudy (anonymous):

@satellite73 just did the rest! :)

OpenStudy (anonymous):

\[\frac{ h√h }{ 7k }\]

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

No prblem!

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