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Mathematics 23 Online
OpenStudy (anonymous):

hi there.. how to solve these?

OpenStudy (anonymous):

the Letter C..

terenzreignz (terenzreignz):

If you can factor the denominator, maybe...

OpenStudy (anonymous):

oh, gosh! :(

OpenStudy (unklerhaukus):

``` \[\frac{x^4+x^3-5x^2-14x-1}{x^5-x^4+4x^3-4x^2+4x-4}\] ``` \[\frac{x^4+x^3-5x^2-14x-1}{x^5-x^4+4x^3-4x^2+4x-4}\]

terenzreignz (terenzreignz):

I don't know how you're meant to factor those, but wolfie says \[\Large (x-1)(x^2+2)^2\]

OpenStudy (anonymous):

eh? how wolfie get that?

OpenStudy (fifciol):

\[x^4(x-1)+4x^2(x-1)+4(x-1)\]

OpenStudy (anonymous):

how??

OpenStudy (fifciol):

now factor x-1

terenzreignz (terenzreignz):

It's called factoring by grouping -.-'

OpenStudy (anonymous):

@Fifciol .. ahh.. got it. :) use synthetic division??

OpenStudy (unklerhaukus):

lets look at the denominator first \[x^5-x^4+4x^3-4x^2+4x-4\] lefts factor the four out \[x^5-x^4+4(x^3-x^2+x-1)\] now lets look at this term \[x^3-x^2+x-1\]

OpenStudy (unklerhaukus):

*lets

OpenStudy (unklerhaukus):

\[x^3-x^2+x-1\] we can try polynomial long division long division|dw:1375784983206:dw|

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