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can anybody explain how to solve this? A 13.5-gram piece of iron reacts with 1.4 grams of oxygen to form a compound. What is the percent composition of this compound? A. 13.5% Fe, 1.4% O B. 24.2% Fe, 8.8% O C. 9.64% Fe, 10.4% O D. 90.6% Fe, 9.4% O E. 18.9% Fe, 81.1% O
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mass % of element(i)=mass of element(i)/Total mass of compound
I am not sure how I would use the given info with that formula....:(
thanks !:)
it can't possibly be B, it has to add up to 100%
D is likely the answer
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Can you please explain how you got D?
Fe%=[1.4/(13.5+1.4)]*100%=9.39597 %
thanks!
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