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Mathematics 8 Online
OpenStudy (anonymous):

I dont understand one bit how to do this, someone please help. Find the point on the terminal side of θ =-3pi/4 that has an x coordinate of -1

OpenStudy (amistre64):

maybe something along these lines arccos(-3pi/4) = x = -1 arcsin(-3pi/4) = y

OpenStudy (amistre64):

might have to introduce a scalar tho

OpenStudy (amistre64):

k arccos(-3pi/4) = -1 k arcsin(-3pi/4) = y

OpenStudy (anonymous):

Can you please explain to me the steps i really want to understand how this is done.

OpenStudy (amistre64):

you are given an angle. that angle is associated with some cosine and sine value. the cosine value relates to x the sine value relates to y so find those values we would use the inverse functions for them

OpenStudy (anonymous):

ok..

OpenStudy (amistre64):

and since they are most likely not on the unit circle, it would have to be some scalar version of them

OpenStudy (amistre64):

another way to approach this is to recognise the pi/4 is 45 degrees; and that -3pi/4 gets us into the left bottom quadrant.

OpenStudy (anonymous):

scalar?

OpenStudy (anonymous):

oh ok

OpenStudy (amistre64):

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