Question

Integral Help Required!!

Answer 1

Attachmnt cntains the question!!

Answer 2

u=sinx+cosx

Answer 3

I get int of sec2x-tan2x dx.correct??

Answer 4

I did rationalising!

Answer 5

not u substitution!!

Answer 6

du=(cosx-sinx) dx

Answer 7

Ya but can u tell me the ans u get??

Answer 8

usinng that substitution
we have
\[\int\limits_{}^{}\frac{ du }{ u }=lnu +C=\ln(sinx +cosx)+C\]

Answer 9

no with the values!!Definite values

Answer 10

it's \[\ln \sqrt2- \ln1=\ln \sqrt2\]

Answer 11

M gtin the same.but ans given is

Answer 12

(ln2)/2

Answer 13

it's the same:
\[\ln \sqrt2= \ln 2^{\frac{ 1 }{ 2 }}=\frac{ \ln 2 }{ 2 }\]

Answer 14

Oh shoot!!

Answer 15

ln1=logbase10 1,r8??

Answer 16

ya,I guess ovios

Answer 17

or is it?

Answer 18

every log of 1 is zero

Answer 19

but with base 1??

Answer 20

it can be 0 or 1??

Answer 21

M confused with logs!!

Answer 22

it doesn't exist log with base of 0 ,1 and all negatives values

Answer 23

So it exist for values>1,right??

Answer 24

yes and between 0 and 1

Answer 25

k....gotcha

Answer 26

Thanks for the help @Fifciol !!

Answer 27

np yw :)