Question

F(X)=X+3,G(Y)=-6SQUARE ROOT OF Y-1
G(F(X))= -6 SQUARE ROOT OF X+3-1 WHAT IS THE DOMAIN OF THE FUNCTION G(F(X))

Answer 1

Are these the equations?
\[f(x) = x + 3\]
\[g(y) = -6\sqrt{y - 1}\]

Answer 2

YUP YUP

Answer 3

THE ANSWERS ARE ONLY WORKS FOR EXAMPLE ONE OF THEM IS ALL NUMBERS LESS THAN OR EQUAL TO -3

Answer 4

No. What I'm asking is if thats what you were trying to write in the question... Is so then \[-6\sqrt{x+2}\]

Answer 5

And don't you mean -2?

Answer 6

x + 3 - 1 = x +2

Answer 7

\[-6\sqrt{X+3-1}\]

Answer 8

Right! So your domain would equal x ≥ -2

Answer 9

"x" is greater than or equal to - 2. http://www.wolframalpha.com/input/?i=-6+sqrt%28x+%2B3+-+1%29

Answer 10

I THINK U DID IT WRONG CUZ THERES NO ANSWERS LIKE THAT THE ONLY NUMVERS WITH THE EQUATIONS ARE -1 AND -3

Answer 11

Did you look at the link? Thats the equation you provided....

Answer 12

If anything. Maybe you mean \[x > -3 \] NOT \[x ≥ -3\]

Answer 13

The lowest domain is -2. \[x ≥ -2\]

Answer 14

\[F(X)=X+3, G(Y)=-6 \sqrt{Y-1} G(F(X))=\sqrt{X+3-1}\]

Answer 15

THATS THE PROBLEM

Answer 16

Oh! I see now... You mean http://www.wolframalpha.com/input/?i=-6+sqrt%28x+%2B3%29+-+1 \[-6\sqrt{x+3} - 1\]

Answer 17

YEAH

Answer 18

ONLY THIS WAY, your answers would look like this:
Domain:
\[x ≥ -3\]
Range:
\[y ≤ -1\]

Answer 19

all numbers lees than o equal t0 -3?

Answer 20

i mean all number less than or equal to -3 would ne my answer

Answer 21

The originals must have looked like...
\[f(x) = x + 3\]
\[g(y) = -6\sqrt{y} -1 \]

Answer 22

yeah

Answer 23

The domain goes up. It can only increase. "All real numbers greater than or equal to -3.

Answer 24

yeah thats what i was thinking of

Answer 25

so we got it right

Answer 26

so it would be all numbers greater than or equal to -3

Answer 27

Yes sir!

Answer 28

\(f(x)=x+3\)
\(g(y)=-6 \sqrt{y-1} \)
\(g(f(x))= -6 \sqrt{x+3-1} \)

\(g(f(x)) = -6\sqrt{x + 2} \)
Domain of g(f(x)) = ?

The radicand can't be negative, so we solve this equation to find the domain:

\(x + 2 \ge 0 \)

\(x \ge -2\)

That's the domain.

Answer 29

I'm uncertain about what the equation was... But @mathstudent55 thats what I did above.

Answer 30

Not, exactly. In the composition of functions, you have -1 outside the root.

Answer 31

Not that one. I mean the one at the very top because he said the options contained only -3 and -1

Answer 32

I see it now. You did get it.

Answer 33

Thanks! :)