help please z^5-3z^2-20/z-2
So what do they want you to do?
Help with what
@jazzyfa30
simplify
How would you like the rational function to be simplified? As the ratio of two polynomials?
Ok so if you use synthetic division it is pretty easy...just remember that any terms that are not there must be represented by 0's
The term simplified is vague with out any context, in different situations different expressions might be seen as simpler as one or another.
ummmmm ok and it dont matter @jack117
You want it in the form $$\frac{Q(z)}{P(z)}$$ Where Q, and P are polynomials with integer coeiffients?
I assume the original expression is \[\frac{z^5-3z^2-20}{z-2}\]
Most symbolic calculators can do this sort of thing, with out much trouble so in general there isn't really need to post for help here if you have a problem like this, you could try somthing free like wolframalpha.
Do you know how to do synthetic division @jazzyfa30
yes paynesdad
??????/////
Ok so what would be your line of coefficients?
\[Z^5-3z^2-20/(z-2)\] multiply by the inverse of 1/(z-2) \[=z^5-3z^2-20z+40\]
@jazzyfa30
@NickChio6 not quite
If the numerator is the first polynomial, then\[\frac{z^5-3z^2-20}{z-2}\]is a division problem that can be done by long division or synthetic division.
ok im starting to get confused
\[=z(z^4-3z-20)+40\]
Ok WIth synthetic division you list all of the coefficients of the thing you are dividing... right?
@NickChio6 no
idk
For example ...\[\frac{x^3-x^2-x-15}{x-3}\]
well it depends on if it is all divisible by z-2 or just -20 is like it is written.
You would do list the coefficientse of the numerator... 1 -1 -1 -15
Does that look familiar at all?
@NickChio6 It is divisible by z-2 you just need to do the synthetic division
Look at what I asked her above... as a clarification of the problem.
@jazzyfa30
nope
So do you know how to do synthetic division or not?
What course is this for?
algebra 2
So you should have learned or should be learning synthetic division.
nvm i got it thanks anyway
How did you do the problem?
ohh i just guessed
:-( That is not going to help you learn how to do this stuff.
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