Question

@ilfy214

Answer 1

Hey! I'm back... anyways lets do this

Answer 2

\[f(x) = -4x + 3\]
\[g(x) = \frac{ 1 }{ x+2 }\]
\[g(f(x)) = \frac{ 1 }{ (-4+3) +2}\]

Answer 3

so what do i do for part 2 @ilfy214

Answer 4

can someone help me finish this

Answer 5

@Directrix @dumbcow @ivettef365

Answer 6

We're looking for g(f(x)) rather than f(g(x)).

Answer 7

is that the first part

Answer 8

huh?

Answer 9

Composition of functions is not commutative.

Answer 10

so are we doing the first part

Answer 11

im confused what do i need to do for the first part

Answer 12

@divagirl421 I did it wrong, this is the right way

f(x) = -4x + 3
g(x) = 1 / x+2

g(f(x)) = 1
--------
-4x+3 +2

Answer 13

which is equal to 1
-----------
-4x +5

Answer 14

you need to substitute the x for (-4x + 3) on function g(x)

Answer 15

now the domain is -4x + 5 = 0
-4x = -5
x = 5/4

so the domain is all real numbers except 5/4

Answer 16

do you understand ?

Answer 17

can you tell me what is part 1 and 2

Answer 18

Part 1: Evaluate g(f(x))

that is 1
g(f(x))= -----------
-4x + 5

Answer 19

Part 2: Determine the domain
-4x + 5 = 0
-4x = -5
x = 5/4

domain are all real numbers except 5/4

Answer 20

ooo ok i understand

Answer 21

on part 1 need to show you work, so you can show this first
f(x) = -4x + 3
g(x) = 1 / x+2

g(f(x)) = 1
--------
-4x+3 +2

Answer 22

thank you:)

Answer 23

yw :)

Answer 24

Back! But you've got it now! :)