Question

Please help

What is the sum of the arithmetic sequence 134, 122, 110 …, if there are 32 terms?

Answer 1

Find the general form, then use that to find the last term. then use the sum of an arithmetic sequence equation to find the sum.\[s = n/2 * (n1 + n32)\]

Answer 2

well the sum is simply

\[S_{n} = \frac{n}{2}[2a + (n -1)d]\]

a = 1st term, n = number of terms and d = common difference

in your question you know n = 32, the 1st term is 134

find the common difference. ..d and then substitute and evaluate.

the value of d will be negative

Answer 3

–1,664

–1,632

–1,600

–1,568

Answer 4

Those are the answers.^

Answer 5

S = [134 - (0)(12)] + [134 - (1)(12)] + [134 - (2)(12)] + . . . + [134 - (31)(12)]

S = (134)(32) - (12)(1 + 2 + 3 + . . . + 31)

S = (134)(32) - (12)(31)(32)/2

Answer 6

All good now, @maria-17 ?

Answer 7

THanksss.

Answer 8

uw!

Answer 9

Good luck to you in all of your studies and thx for the recognition! @maria-17

Answer 10

Can you help me with one more?

Answer 11

Sure, why not? Best though to close this one and just start another post.