Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

What is the vertex of y = 2|x| – 1 ?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (zzr0ck3r):

there are lots of confusing stuff about this question, first off the vertex is a ordered pair (x,y) not a graph. so I don't see what the options are for second off 2|x|-1 looks like this|dw:1375825770304:dw| so I really don't see what the graphs have to do with this, as none of them are the graph of the function you posted

OpenStudy (anonymous):

thats the question and the options. its asking for the vertex

OpenStudy (zzr0ck3r):

u sure it was not -(|x|+1)?

OpenStudy (zzr0ck3r):

or something like that...

OpenStudy (anonymous):

ohhh my bad

OpenStudy (anonymous):

the question is Select the graph of y = – |x + 3| + 2

OpenStudy (zzr0ck3r):

ahh do you know what the graph of y = |x| looks like?

OpenStudy (anonymous):

is it a V?

OpenStudy (zzr0ck3r):

yes, at the origin

OpenStudy (zzr0ck3r):

|x+3| will move it 3 units to the left |x+3|+1 will then move it to the left 3 units and up 1 unit -|x+3|+1 will then move it to the left 3 units and up 1 unit and then flip it upside down

OpenStudy (jdoe0001):

hmmm so, look at the absolute value expression only |x| what values for "x" would make that 0?

OpenStudy (zzr0ck3r):

so if y=|x| is a V at the origin, then was does it look like after the transformation?

OpenStudy (anonymous):

its gonna be an upside down V

OpenStudy (anonymous):

@zzr0ck3r ???

OpenStudy (jdoe0001):

what values for |x| will make that = 0?

OpenStudy (zzr0ck3r):

they are all upside down v's

OpenStudy (anonymous):

yea but which graph is correct? @zzr0ck3r

OpenStudy (anonymous):

@jdoe0001 which graph is correct then?

OpenStudy (jdoe0001):

well, you'd want to find the vertex first to know where the "V" ends up

OpenStudy (jdoe0001):

zzr0ck3r 's picture looks ok, just need some translation

OpenStudy (anonymous):

zzr0ock3r's graph is from the wrong equation

OpenStudy (jdoe0001):

understood, but you just want the vertex, no the graph I understood

OpenStudy (anonymous):

no i want to know which is the right graph of y = – |x + 3| + 2

OpenStudy (jdoe0001):

y = A( Bx + C ) + D A = shrinks or expands the graph, A > 0, opens upwards, A < 0, opens downwards C = horizontal shift, C > 0, to the left, C < 0, to the right D = vertical shift, D > 0, up, D < 0, down

OpenStudy (jdoe0001):

so opens downwards, and it has horizontal and vertical translations

OpenStudy (jdoe0001):

but just finding the vertex though, those shifts are pretty much visible and you can find that by just setting the absolute expression to 0, and solve for "x"

OpenStudy (anonymous):

so is the answer B?

OpenStudy (jdoe0001):

hmm the original equation shows => y = 2|x| – 1 and I assume the pictures relate to that, no y = – |x + 3| + 2

OpenStudy (anonymous):

is it C?

OpenStudy (anonymous):

i thinks it either C or D

OpenStudy (anonymous):

@jdoe0001 ?

OpenStudy (jdoe0001):

I dunno which one the graphs pertain to

OpenStudy (jdoe0001):

why not just find the vertex of it? that way you can graph it :)

OpenStudy (jdoe0001):

set the absolute expression to 0

OpenStudy (anonymous):

like this y = – |x + 3| + 2= 0????

OpenStudy (jdoe0001):

well, the simpler way will be what value of "x" makes | x + 3 | equals to 0?

OpenStudy (anonymous):

|-3+3|=0

OpenStudy (jdoe0001):

\(\bf y = – |x + 3| + 2\\ |(\color{red}{-3})+3| \color{red}{+2}\\ (\color{red}{-3}, \color{red}{2}) \Leftarrow vertex\)

OpenStudy (jdoe0001):

|dw:1375828469401:dw|

OpenStudy (anonymous):

thanks a lot

OpenStudy (jdoe0001):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!