What is the vertex of y = 2|x| – 1 ?
there are lots of confusing stuff about this question, first off the vertex is a ordered pair (x,y) not a graph. so I don't see what the options are for second off 2|x|-1 looks like this|dw:1375825770304:dw| so I really don't see what the graphs have to do with this, as none of them are the graph of the function you posted
thats the question and the options. its asking for the vertex
u sure it was not -(|x|+1)?
or something like that...
ohhh my bad
the question is Select the graph of y = – |x + 3| + 2
ahh do you know what the graph of y = |x| looks like?
is it a V?
yes, at the origin
|x+3| will move it 3 units to the left |x+3|+1 will then move it to the left 3 units and up 1 unit -|x+3|+1 will then move it to the left 3 units and up 1 unit and then flip it upside down
hmmm so, look at the absolute value expression only |x| what values for "x" would make that 0?
so if y=|x| is a V at the origin, then was does it look like after the transformation?
its gonna be an upside down V
@zzr0ck3r ???
what values for |x| will make that = 0?
they are all upside down v's
yea but which graph is correct? @zzr0ck3r
@jdoe0001 which graph is correct then?
well, you'd want to find the vertex first to know where the "V" ends up
zzr0ck3r 's picture looks ok, just need some translation
zzr0ock3r's graph is from the wrong equation
understood, but you just want the vertex, no the graph I understood
no i want to know which is the right graph of y = – |x + 3| + 2
y = A( Bx + C ) + D A = shrinks or expands the graph, A > 0, opens upwards, A < 0, opens downwards C = horizontal shift, C > 0, to the left, C < 0, to the right D = vertical shift, D > 0, up, D < 0, down
so opens downwards, and it has horizontal and vertical translations
but just finding the vertex though, those shifts are pretty much visible and you can find that by just setting the absolute expression to 0, and solve for "x"
so is the answer B?
hmm the original equation shows => y = 2|x| – 1 and I assume the pictures relate to that, no y = – |x + 3| + 2
is it C?
i thinks it either C or D
@jdoe0001 ?
I dunno which one the graphs pertain to
why not just find the vertex of it? that way you can graph it :)
set the absolute expression to 0
like this y = – |x + 3| + 2= 0????
well, the simpler way will be what value of "x" makes | x + 3 | equals to 0?
|-3+3|=0
\(\bf y = – |x + 3| + 2\\ |(\color{red}{-3})+3| \color{red}{+2}\\ (\color{red}{-3}, \color{red}{2}) \Leftarrow vertex\)
|dw:1375828469401:dw|
thanks a lot
yw
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