Question

Help me please with (a^4 b^-5) ^-4
I've been trying to get this for an hour and I can't do it

Answer 1

what do you have to do simplify it?

Answer 2

I'm not sure it just says that my answer should only contain positive exponents

Answer 3

oh alright... so you just gotta make it into a fraction... when you multiply the exponents remember the signes will change then negative exponents go into the denominator.. try it and tell me what you got and ill check it\

Answer 4

I do not know how to make it into a fraction

Answer 5

\(\bf \Large a^{-n} = \cfrac{1}{a^n}\)

Answer 6

you just have to put the negative exponents in the denominator... i.e x^5v^-5= (x^5)/(v^5)

Answer 7

What is N?

Answer 8

it dnsnt rlly matter what it is just that it is negative and he moved it into the denominator

Answer 9

so (a^4/b^5) ^-4 ???

Answer 10

all you have to do is move the whole () down think of it as this.. \[\frac{(a^4b^{-5})^{-4}}{1}= \frac{1}{(a^4b^{-5})^4}\] notice atfer we fliped the () down we got a positive 4

Answer 11

\(\bf \Large a^{-cheeseburger} = \cfrac{1}{a^{cheeseburger}}\)

Answer 12

lol

Answer 13

Why didn't the exponets of a abd b change when you put it in the denominator

Answer 14

*and

Answer 15

then you gotta distribute your exponent and move some more stuff around\[\frac{ 1 }{(a ^{8}b ^{-20}) }\] then you gotta move b upp and it becomes positive

Answer 16

could u answer my last question first? I don't get that part

Answer 17

a^16 not 8 haha