Question

x^-2+x^-1+1over x^-2-x eliminate the complex fractioons

Answer 1

\[\frac{x^{-2}+x^{-1}+1}{x^{-2}-x}\] like that?

Answer 2

multiply top and bottom by \(x^2\) to get
\[\frac{x^{-2}+x^{-1}+1}{x^{-2}-x}\times \frac{x^2}{x^2}\]
\[=\frac{1+x+x^2}{1-x^3}\]

Answer 3

we are not done though, denominator factors
\[\frac{1+x+x^2}{(1-x)(1+x+x^2)}\] and now you can cancel

Answer 4

giving a final answer of
\[\frac{1}{1-x}\]

Answer 5

Yea exactly thank you for the help

Answer 6

yw