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Find the sum of the series 12∈n-1(2n+1)?
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@Ashleyisakitty Can you re-write that in LATex/equation editor?
\[\sum_{n-1}^{12}(2n+1)\]
any ideas?
You start at n = -1... and keep going until you get to 12. -1 + 1 + 3 + 5 + 7 + 9 + ....+ n11+ n12
*starting where you left off* 11+13+15+17+19+21. What do i do next?
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add them on your calculator.
120
That is the sum of the terms starting at n = -1 to n = 12.
these are what i have to chose from
Alright Just making Sure that n =-1 or is it 1?
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Under the E thingy? Yes it is n-1
if youre talking at the end it is +1
Here is the summation of an arithmetic sequence.\[Sn = \frac{ n }{ 2 } [2a1+(n-1)d]\]
You were correct the answer was 144.
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