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Mathematics 16 Online
OpenStudy (ashleyisakitty):

Find the sum of the series 12∈n-1(2n+1)?

OpenStudy (anonymous):

@Ashleyisakitty Can you re-write that in LATex/equation editor?

OpenStudy (ashleyisakitty):

\[\sum_{n-1}^{12}(2n+1)\]

OpenStudy (ashleyisakitty):

any ideas?

OpenStudy (anonymous):

You start at n = -1... and keep going until you get to 12. -1 + 1 + 3 + 5 + 7 + 9 + ....+ n11+ n12

OpenStudy (ashleyisakitty):

*starting where you left off* 11+13+15+17+19+21. What do i do next?

OpenStudy (anonymous):

add them on your calculator.

OpenStudy (ashleyisakitty):

120

OpenStudy (anonymous):

That is the sum of the terms starting at n = -1 to n = 12.

OpenStudy (ashleyisakitty):

these are what i have to chose from

OpenStudy (anonymous):

Alright Just making Sure that n =-1 or is it 1?

OpenStudy (ashleyisakitty):

Under the E thingy? Yes it is n-1

OpenStudy (ashleyisakitty):

if youre talking at the end it is +1

OpenStudy (anonymous):

Here is the summation of an arithmetic sequence.\[Sn = \frac{ n }{ 2 } [2a1+(n-1)d]\]

OpenStudy (anonymous):

You were correct the answer was 144.

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