Question

CHECK PLEASE! Assume the triangle has the given measurements. Solve for the remaining sides and angles.
C = 95º , a = 1/2 , and b = 1/3

Answer 1

use law of cosines to get a
\[\sqrt{(\frac{1}{2})^2+(\frac{1}{3})^2-2\frac{1}{2}\frac{1}{3}cos(95)}=a\]

Answer 2

Okay. Yes that what I have!
a = 0.6246

Answer 3

now use law of sines to get A
\[\frac{sin(95)}{0.6246}=\frac{sin(\theta)}{\frac{1}{2}}\]

Answer 4

Oh okay nevermind then... And I do that for 1/3 also?

Answer 5

Or should I just subtract my findings?

Answer 6

either way

Answer 7

those two equations wont help, try it and you will se what I mean

Answer 8

Oh damn. Yes, I see now....

Answer 9

This is what I have found so far 1.09392 = 2 sin(theta)

Answer 10

And the other angle is 1.09392 = 3 sin(theta)

Answer 11

@ankit042 @agent0smith @genius12 @Luigi0210 @Luis_Rivera How do I go on from here?

Answer 12

1.09392 = 2 sin(theta)

If this is what you have, do you just need help solving for theta...?

Answer 13

Yes! How do I find the angle for A and B?

Answer 14

I know that 1.09392 = 2 sin(theta) is for A while 1.09392 = 3 sin(theta) is for B!

Answer 15

\[\Large \frac{\sin(95)}{0.6246}=\frac{\sin A }{\frac{1}{2}}\]use this for A.

Answer 16

Oh wait, so thats it? Is there no way to break it down any further?

Answer 17

Put your calculator into degrees mode, it's in radians and your numbers aren't right.

Answer 18

1.09392 = 2 sin(theta) isn't correct... you used radians, the 95 is in degrees.

Answer 19

Now I have 1.59493 = 3 sin(B) and 1.59493 = 2 sin(A)

Answer 20

Solving for A and B is easy now. For 1.59493 = 3 sin(B) , divide both sides by 3, then use inverse sine (sin^-1)

1.59493 = 2 sin(A) divide both sides by 2, then use inverse sine.

Answer 21

Thanks!

Answer 22

I got A = 52.888705 and B = 32.11655562

Answer 23

Those two add up to 85, and with the other angle being 95, the three add up to 180 degrees, which is a good sign.

Answer 24

WOO-HOO!! Thank you!